Эх сурвалжийг харах

fix代码双引号错误 (#472)

xin zhao 7 жил өмнө
parent
commit
866f646694
1 өөрчлөгдсөн 5 нэмэгдсэн , 5 устгасан
  1. 5 5
      eBook/11.14.md

+ 5 - 5
eBook/11.14.md

@@ -62,7 +62,7 @@ func (cs Cars) Map(f func(car *Car) Any) []Any {
 
 ```go
 allNewBMWs := allCars.FindAll(func(car *Car) bool {
-       return (car.Manufacturer == “BMW”) && (car.BuildYear > 2010)
+       return (car.Manufacturer == "BMW") && (car.BuildYear > 2010)
 })
 ```
 
@@ -75,13 +75,13 @@ func MakeSortedAppender(manufacturers[]string)(func(car*Car),map[string]Cars) {
 	for _, m := range manufacturers {
 		sortedCars[m] = make([]*Car, 0)
 	}
-	sortedCars[“Default”] = make([]*Car, 0)
+	sortedCars["Default"] = make([]*Car, 0)
 	// Prepare appender function:
 	appender := func(c *Car) {
 		if _, ok := sortedCars[c.Manufacturer]; ok {
 			sortedCars[c.Manufacturer] = append(sortedCars[c.Manufacturer], c)
 		} else {
-			sortedCars[“Default”] = append(sortedCars[“Default”], c)
+			sortedCars["Default"] = append(sortedCars["Default"], c)
 		}
 
  	}
@@ -92,10 +92,10 @@ func MakeSortedAppender(manufacturers[]string)(func(car*Car),map[string]Cars) {
 现在我们可以用它把汽车分类为独立的集合,像这样:
 
 ```go
-manufacturers := []string{“Ford”, “Aston Martin”, “Land Rover”, “BMW”, “Jaguar”}
+manufacturers := []string{"Ford", "Aston Martin", "Land Rover", "BMW", "Jaguar"}
 sortedAppender, sortedCars := MakeSortedAppender(manufacturers)
 allUnsortedCars.Process(sortedAppender)
-BMWCount := len(sortedCars[“BMW”])
+BMWCount := len(sortedCars["BMW"])
 ```
 
 我们让这些代码在下面的程序 cars.go 中执行: